Question

∆SHR~∆SUU in ∆SHR SH=4cm,HR=4cm,SR=4.8cm and SH/SV=5/3 then draw ∆SVU.
​

Answer 1

ΔSVU is constructed SV = 2.4  , VU = 2.4  and  SU = 2.88 cm

Given:

• ∆SHR~∆SVU   ( correction  in Question)
• In ∆SHR SH=4cm, HR=4cm, SR=4.8cm
• SH/SV=5/3

To Find:

• Draw ∆SVU

Solution:

• Ratio of corresponding sides of Similar triangle is same.

Step 1:

∆SHR~∆SVU  Hence

SH/SV = HR/VU  = SR/SU

Step 2:

Substitute SH=4cm, HR=4cm, SR=4.8cm  and equate each ratio with 5/3

4/SV =4/VU  = 4.8/SU  = 5/3

=> SV = 2.4  , VU = 2.4  and  SU = 2.88 cm

We can not draw 2.88 cm using ruler Hence use construction from triangle SHR to construct triangle SVU

Construction:

Step 1: Draw a line segment  SH = 4 cm

Step 2: Using compass width = 4 cm and taking H as center draw an arc

Step 3: Using compass width = 4.8 cm and taking S as center draw an arc intersecting arc drawn in previous step at R

Step 4: Join HR and SR

Step 5 : Draw an Acute angle HSX

Step 6: Take 5 points of ray SX from S at Equal Distance using suitable compass width ( Labelling 1 to 5)

Step 7 : Join 5th Point  with H

Step 8 : Using Set square draw a line parallel to 5H from 3 intersecting SH at V

Step 9 : Using Set square draw a line parallel to HR from V intersecting SR at U

Hence ΔSVU is constructed

(In your Question ∆SHR~∆SUU  should have been  ∆SHR~∆SVU )

Answer 2

Step-by-step explanation:

hope it is helpful......