Question

∆ SHR ∼ ∆ SVU. In ∆ SHR, SH = 4.5 cm, HR = 5.2 cm, SR = 5.8 cm and
SH/SV = 5/3
then draw ∆ SVU.
​

Answer 1

Answer:

Δ SHR∼ Δ SVU, in Δ SHR, SH=4.5cm, HR=5.2cm, SR=5.8cm and  

SV

SH  

=  

5

3

Construct Δ SVU.

Medium

Solution

 

Given ΔSHR∼ΔSVU.

In ΔSHR,SH=4.5cm,HR=5.2cm,SR=5.8cm and  

SV

SH

​

=  

5

3

​

 

We have to construct ΔSVU

Steps of construction:

Draw a line segment SH=4.5cm

With S as center, draw an arc of the radius 5.8cm

With H as center, draw an arc of the radius 5.2cm, that cuts the previously drawn arc at R. Join RS and RH.

Take a point V in the extended line SH such that SH:SV=3:5.

Draw VU parallel to HR.

Answer 2

Answer:

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