Shrava travels 8 km towards east and then travels 12 km towards north .he turns lrft to travel 6 km further. now he travels 5 km to his right followed by 8 km to his left .how far is he approximately from his initial position?
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answer iss 18 km
H2 = B2 + P2
H2 = 8×8+17×17
= 64 + 289
= 353
= √353
= 18.7
= 18 km approx.
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