Physics, asked by jahid1970, 11 months ago

Shravan and ronny decided to go on a holiday to b on a particular day from a. Shravan leaves for b at 10 :00 am , at speed of 72km/hr. Ronny leaves for b at 10:30 am same day as shravan left. At what speed should ronny travel to catch up with shravan in 4 hours?[in kmph]

Answers

Answered by sagarabhiabhishek
0

Answer: According to question

We can say that Distance travelled by both person is equal

so Distance travelled bt Shravan = Distance travelled by Ronny

72 x 4.5 = Velocity x 4

velocity = \frac{324}{4}

Velocity = 81 Km/h

Similar questions