Shree Travels at a distance of 12 km from her house to school by a bus at 20km/hr and returns home at 16km/hr.
1. Calculate the time required to reach school from home. 2. Find out the time required to reach home from school. 3. Determine the aver distance of the entire journey
Answers
Answer:
1).Distance between home and school = 12 km
Speed of bus from her house to school = 20 km/hr
Time required to reach the school from the home = Distance travelled/Spped
Time= 12km/20km/hr
Time= 3/5 hr
Time=3/5*60 min
Time = 3*12 min
Time = 36 min
Hence, The time required to reach the school from the home =36 minutes.
2) Distance =12 km
Speed =16 km/hr
Time = Distance travelled /Speed
Time= 12km/16km/hr
Time = 3/4 hr
Time= 3/4*60 min
Time= 3*15 min
Time= 45 min
Hence, The time required to reach the school from the home = 45 minutes.
3)Average distance =Total distance / 2 km
Average distance = (12+12) / 2 = 24/2 = 12 km
Average speed =Total distance travelled /Total time taken
Average speed = (12+12) km / 36 min+45 min
=24 km / 3/5+3/4 hr
=24km / (12+15)/20 hr
=24 km / 27/20 hr
=24 km *27/20 hr
=648 km / 20 hr
=32.4 km/hr.
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Answer:
1).Distance between home and school = 12 km
Speed of bus from her house to school = 20 km/hr
Time required to reach the school from the home = Distance travelled/Speed
Time= 12km/20km/hr
Time= 3/5 hr
Time=3/5 x 60 min
Time = 3 x12 min
Time = 36 min
Hence, The time required to reach the school from the home =36 minutes.
2) Distance =12 km
Speed =16 km/hr
Time = Distance travelled /Speed
Time= 12km/16km/hr
Time = 3/4 hr
Time= 3/4x60 min
Time= 3x15 min
Time= 45 min
Hence, The time required to reach the school from the home = 45 minutes.
3)Average distance =Total distance / 2 km
Average distance = (12+12) / 2 = 24/2 = 12 km
Average speed =Total distance travelled /Total time taken
Average speed = (12+12) km / 36 min+45 min
=24 km / 3/5+3/4 hr
=24km / (12+15)/20 hr
=24 km / 27/20 hr
=24 km *27/20 hr
=648 km / 20 hr
=32.4 km/hr.