Math, asked by janvi1530, 4 months ago

shreya walks around a park whose lenght = 31 m and breadth = 14 m. Find the distance covered by shreya if she walks around the park 7 times​

Answers

Answered by Anonymous
8

Required Answer :

Given -

• Shreya walks around a park whose Length and Breadth are 31 m and 14 m respectively

To Find -

• The distance covered by her if she walks around the park 7 times

Formula Used -

• Perimeter of Rectangle = 2 × ( Length + Breadth )

Solution -

As the words, Length and Breadth are used, obviously we are given with a 2 dimensional shape which is Rectangle, and as the word around is used, we have to take out the Perimeter of the Rectangle. The formula used is Perimeter of Rectangle = 2 × ( Length + Breadth ), and when we are done with finding the Perimeter, we will just multiply it with 7, why multiply? because the word times is used, and 7 times that means we have to multiply the Perimeter with 7, so let's do it!

Perimeter of Rectangle = 2 × ( Length + Breadth )

Perimeter of Rectangle = 2 × ( 31 + 14 )

Perimeter of Rectangle = 2 × 45

Perimeter of Rectangle = 90 m

So, Perimeter of the Park is 90 m

Now, we have the Perimeter of the Park, let's find out the distance covered by her if she walks around the park 7 times then!

90 × 7 = 630 ( Kindly refer the attachment )

Hence, Multiplied!

The distance covered by her if she walks around the park 7 times is 630 m

___________________________

Attachments:
Answered by Anonymous
9

\large{\underbrace{\underline{\sf{Understanding\; the\; Question}}}}

Here in this question, concept of perimeter of rectangle is used. We have given a statement that Shreya walks around a park 7 times. We know that boundary of a given figure is called it's perimeter. Shreya walks around a park it means she walked along perimeter of the park. As she moved 7 times around park, so we have to find 7 times of the perimeter of park.

So let's start :)

\rule{380}{2}

~Given:-

• Length of park =31m

• Breadth of park=14m

\rule{380}{2}

~To find:-

• 7 times of the perimeter of park

\rule{380}{2}

~Formula used:-

Perimeter of rectangle=2(Length+ Breadth)

\rule{380}{2}

~Solution:-

Perimeter of park=2(Length+Breadth)

Perimeter of park=2(31m+14m)

Perimeter of park=2(45m)

Perimeter of park=90m

It means Shreya walked 90m in one round around the park.

\rule{380}{2}

Distance traveled by Shreya in 7 rounds around the park:-

Distance traveled by Shreya=7× Perimeter

Distance traveled by Shreya=7×90 m

Distance traveled by Shreya=630 m

∵  Distance covered by Shreya in 7 rounds is 630 metre.

\rule{380}{2}

Diagram:

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 31cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 14 cm}\put(2,1.4){\Large{\sf{Park}}}}\end{picture}

\rule{380}{2}

\Large{\underbrace{\underline{\sf{More\;Important\; Formulas}}}}

• Area of rectangle=Length×Breadth

• Area of square=Side²

• Area of ∆=½×Base×Height

• Area of circle=πr²

• Area of trapezium=½×(Sum of || sides)×Height

• Perimeter of circle=2πr

• Perimeter of rhombus=4×Side

• Perimeter of square=4×Side

\rule{380}{2}

Kindly visit web for better understanding.

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