Shreyansh Tiwari
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in gp 2,6,18,54.......13122 the product of 3rd term from beginning and 3rd term from last is 26244
Solve it i will mark u brainiliest.
Anonymous:
oh we have to prove ?
Answers
Answered by
1
Hey mate
.
Here is your Answer
.
It has the simple formula-
nth digit of the series is given by= (n-1)*3
Where n= 1 is equal to 2
So the next terms of the given equation is-
=> 54*3= 162
=> 162*3= 486
=> 486*3= 1458
=> 1658*3= 4374
So the 8th term of the series is 4374
.
follow me
.
Here is your Answer
.
It has the simple formula-
nth digit of the series is given by= (n-1)*3
Where n= 1 is equal to 2
So the next terms of the given equation is-
=> 54*3= 162
=> 162*3= 486
=> 486*3= 1458
=> 1658*3= 4374
So the 8th term of the series is 4374
.
follow me
Answered by
14
3 rd term = 18 .
3 rd term from the end = ?
Ratio = 6/2 = 3
So 3 rd term can be found from the end by dividing .
13122/3 = 4374
4374/3 = 1458
The product of 1458 * 3 = 26244 .
Hence proved .
So its true .
But what to find actually?
Its incomplete .
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