Question

shrinivasan deposited ₹36458 in the bank.in the next two years he deposited ₹2305 an₹57982.find the.total amount.

Answer 1

We are given the following information,

First deposit = ₹ 36,458
Second deposit = ₹ 2,305
Third deposit = ₹ 57,982

Since we are not given any rate percent and/or any interest is being calculated, hence we will simply add the deposits and our sum will be the answer.

Total Amount = First Deposit + Second Deposit + Third Deposit
Total Amount = ₹ 36,458 + ₹ 2,305 + ₹ 57,982
Total Amount = ₹ 38,763 + ₹ 57,982

On simplifying further we get,

Total Amount = ₹ 96,745

Answer 2

$\huge \bold {\mathfrak {hey}}$

Shrinivasan deposited first time = ₹ 36458
Shrinivasan deposited Second time = ₹ 2305
Shrinivasan deposited Third time = ₹57982

To find the total amount we should add all those rupees to get Shrinivasan total amount.

So,

Now,

Total amount = First deposit + second deposit + third deposit

Total amount = 36458 + 2305 + 57982

Total amount = ₹ 96,745


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