Question

Shubham runs from A to B and Vishal runs from B to A towards each other, after meeting each other Shubham reached B in 9 hours and Vishal reached A in
16 hours. If Shubham's speed is 45 km/hour, find the speed of Vishal.
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Answer 1

$\boxed{Question:-}$

Shubham runs from A to B and Vishal runs from B to A towards each other, after meeting each other Shubham reached B in 9 hours and Vishal reached A in

Shubham runs from A to B and Vishal runs from B to A towards each other, after meeting each other Shubham reached B in 9 hours and Vishal reached A in16 hours. If Shubham's speed is 45 km/hour, find the speed of Vishal?

$\boxed{Solution:-}$

→Subham's Speed=45km/hr[S2]

→Time taken by Shubam=9hrs[T2]

→Time Taken by Vishal=16hrs[T1]

Let Vishal's Speed=x km/hr[S1]

Using Formula↓

$\frac{\sqrt{T2}}{T1}$=$\frac{S1}{S2}$

→$\frac{\sqrt{9}}{16}$=$\frac{x}{45}$

→$\frac{3}{4}$=$\frac{x}{45}$

Shift 45 from RHS-->LHS ↓

=>$\frac{3}{4}$×45=x

→$\frac{135}{4}$=x

→$\boxed{x=33.75}$

$\mathcal{BE \: BRAINLY}$

Answer 2

||✪✪ QUESTION ✪✪||

Shubham runs from A to B and Vishal runs from B to A towards each other, after meeting each other Shubham reached B in 9 hours and Vishal reached A in

16 hours. If Shubham's speed is 45 km/hour, find the speed of Vishal. ? ( Nice Question ).

|| ✰✰ ANSWER ✰✰ ||

❁❁ Refer To Image First .. ❁❁

with Image we proved A formula for This Problem , That,

☙☘ (S1/S2) = √(T2/T1) ☙☘

⟪ where S1 is Speed from point A and S2 is Speed from Point B , and T2 is Time to Reach at A after Meeting point , and T1 is Time to Reach at B after Meeting point.⟫

__________________

with This we can say that :-

➺S1 = 45 km/h

➺ S2 = Let x km/h

➺ T1 = 9 hours.

➺ T2 = 16 Hours.

Putting All values in Our Formula now, we get,,

➻ (45/x) = √(16/9)

➻ (45/x) = 4/3

Cross - Multiply

➻ 4x = 45 * 3

➻ 4x = 135

Dividing both sides by 4,

➻ x = 33.75 km/h.

Hence, Speed of Vishal is 33.75km/h.