Shubham travels 760 km to his home partly by train and partly by Car. He takes 8 hours if he travels
160 km by train and the rest by Car. He takes 12 minute more if he travels 240 km by train and the
reset by Car. Find the speed of the train & the Car respectively (in km/hr).
(A) 40, 80
(B) 60, 120
(C) 80,100
(D) 100,120
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Answer:
Let the speed of train be xkm/hr
and the speed car be ykm/hr respectively.
We know that Speed=TimeDistance⇒Time=SpeedDistance
In Case 1
Distance travelled by train = 160km
Distance travelled by car = (760-160)km = 600km
Time taken by train+Time taken by car = 8 hours
Hence the equation becomes
x160+y600=8
In case 2
Distance travelled by train = 240km
Distance travelled by car = (760-240)km = 520km
Time taken by train+Time taken by car = 8 hours+12 minutes
Hence the equation becomes
x240+y520=541......(2)
Hence we get two equations
x160+y600=8.........(1)x240+y520=541......(2)
Letx1=pandy1=q
Hence we get equations
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