Question

Shveta distributed y kg rice and x kg wheat to each family which comes under BPL of her society where

x and y are the natural numbers which satisfy 8x + 3y = 96 and x < 5. If number of beneficiaries family is 30,

then find the total quantity of rice and wheat respectively distributed by Shveta.​

Answer 1

Given :- x and y are the natural numbers which satisfy 8x + 3y = 96 and x < 5. If number of beneficiaries family is 30, then find the total quantity of rice and wheat respectively distributed by Shveta.

Solution :-

→ 8x + 3y = 96

since x is a natural number and x < 5 . putting value of x as 1,2,3 and 4 we get,

at x = 1,

→ 8 + 3y = 96

→ 3y = 96 - 8 = 88

→ y = 88/3 ≠ not a natural number .

at x = 2,

→ 16 + 3y = 96

→ 3y = 96 - 16 = 80

→ y = 80/3 ≠ not a natural number .

at x = 3,

→ 24 + 3y = 96

→ 3y = 96 - 24 = 72

→ y = 72/3 = 24 = A natural number .

at x = 4,

→ 32 + 3y = 96

→ 3y = 96 - 32

→ 3y = 64

→ y = 64/3 ≠ not a natural number . .

therefore, x(wheat) = 3kg and y(Rice) = 24kg.

Learn more :-

Consider the sequence defined by ak=1/k2-k for k ≥ 1. Given that aM + aM + 1 + …………+ aN – 1=1/29 for positive integers M...

brainly.in/question/42384271

(c)

75. From a number M subtract 1. Take the reciprocal of

the result to get the value of 'N'. Then which of the

followi...

brainly.in/question/39499253