Math, asked by Akanksha18012008, 12 days ago

Shweta distributed y kg rice and x kg wheat to each family which comes under BPL of her society where x and y are the natural numbers which satisfy 8x+3y =96 and x​

Answers

Answered by sandhya5nir
6

Answer:

8x+3y=96

8x+y=96÷ 3

8x+y=32

x+y=32÷ 8

x+y=4

x=4-y

y=4-x

Answered by amitnrw
13

Given :  

Shweta distributed y kg rice and x kg wheat to each family which comes under BPL of her society where x and y are the natural numbers which satisfy 8x+3y =96 and x<5 .

The number of beneficiaries family is 30

To  find   :  the value of x and y respectively distributed by Shweta​

x<5

x is natural number hence x can be 1 , 2 , 3 or 4 only

8x +3y =96

x = 1  => y  = 88/3    not a natural number

x =2  => y  = 80/3   not a natural number

x =3  =>  y = 24       not a natural number

x = 4 => y  = 64/3  not a natural number

Hence x  = 3   and y = 24  is only possible solution  

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