Shweta distributed y kg rice and x kg wheat to each family which comes under BPL of her society where x and y are the natural numbers which satisfy 8x+3y =96 and x
Answers
Answer:
8x+3y=96
8x+y=96÷ 3
8x+y=32
x+y=32÷ 8
x+y=4
x=4-y
y=4-x
Given :
Shweta distributed y kg rice and x kg wheat to each family which comes under BPL of her society where x and y are the natural numbers which satisfy 8x+3y =96 and x<5 .
The number of beneficiaries family is 30
To find : the value of x and y respectively distributed by Shweta
x<5
x is natural number hence x can be 1 , 2 , 3 or 4 only
8x +3y =96
x = 1 => y = 88/3 not a natural number
x =2 => y = 80/3 not a natural number
x =3 => y = 24 not a natural number
x = 4 => y = 64/3 not a natural number
Hence x = 3 and y = 24 is only possible solution
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