Question

Shweta observes lightning in her area. She hears the sound
5 s after she observed lighting. How far is she from the
place where lightning occurs if speed of sound in air is 330
ms-1
A) 1.65 km
B) 2.55 km
C 3.65 km
D) 4.55 km​

Answer 1

Answer:

1.65 km

Explanation:

Here,

Distance between Shweta and that point be 'd'

Time taken = 5 s.

Using speed = distance/time

=> 330 m/s = d/5s

=> (330 m/s) x 5s = d

=> 330 x 5 m = d

=> 1650 m = d

=> 1650 (1/1000) km = d {1m=1/1000 km}

=> 1.65 km = d

Answer 2

Answer:

$\underline{\boxed{\red{\large{\rm{Distance = 1.65 \: km}}}}}$

Explanation:

Given,

• Time taken = 5 secs
• Speed = 330 ms⁻¹

To find :

• The distance between Shreya and the point from where the lightning occurs.

Solution :

Let us consider the distance be 'x' m.

We know that,

$\longrightarrow \bf Speed = \dfrac{Distance}{Time}$

$\longrightarrow \tt Distance = Speed \times Time$

$\longrightarrow \tt Distance = 330 \: ms^{-1} \times 5 s$

$\longrightarrow \tt Distance = 1650 \: m$

Converting m to km,

$\longrightarrow \boxed{\bf Distance = 1. 65 \: km}$

Hence, the distance between Shreya and the point from where the lightning occurred is 1.65 km