Question

Shyam deposited 4000 rs in a bank to earn interest, at the rate of 19/2 % per annum. find the amount which Shyam will get from the bank after 2 years when interest being compounded annually. How much is the compound interest? (answer by simple interest method)​

Answer 1

Answer:

hence Shyam deposited RS 4000 in the bank to earn interest at the rate of 9 1/2% per annum.

so his compound interest will be ________

\begin{gathered}(4000(1 + \frac{ \frac{19}{2} }{100} )^{2} )- 4000 \\ =( 4000(1 + \frac{19}{200} )^{2}) - 4000 \\ = (4000 \times \frac{219}{200} \times \frac{219}{200} ) - 4000\\ = (4 \times 219 \times \frac{219}{20} ) - 4000\\ =(9592.2 - 4000)rs \\ = 5592.2 \: rs\end{gathered}

(4000(1+

100

2

19

)

2

)−4000

=(4000(1+

200

19

)

2

)−4000

=(4000×

200

219

×

200

219

)−4000

=(4×219×

20

219

)−4000

=(9592.2−4000)rs

=5592.2rs

hope this helps...

Answer 2

Answer:

4796

explained

4000(1+19/2/100)^2

4000(219/200)^2

4000(1.99025)^2

4000*1.99025

4796