Shyam deposited 4000 rs in a bank to earn interest, at the rate of 19/2 % per annum. find the amount which Shyam will get from the bank after 2 years when interest being compounded annually. How much is the compound interest? (answer by simple interest method)
Answers
Answered by
0
Answer:
hence Shyam deposited RS 4000 in the bank to earn interest at the rate of 9 1/2% per annum.
so his compound interest will be ________
\begin{gathered}(4000(1 + \frac{ \frac{19}{2} }{100} )^{2} )- 4000 \\ =( 4000(1 + \frac{19}{200} )^{2}) - 4000 \\ = (4000 \times \frac{219}{200} \times \frac{219}{200} ) - 4000\\ = (4 \times 219 \times \frac{219}{20} ) - 4000\\ =(9592.2 - 4000)rs \\ = 5592.2 \: rs\end{gathered}
(4000(1+
100
2
19
)
2
)−4000
=(4000(1+
200
19
)
2
)−4000
=(4000×
200
219
×
200
219
)−4000
=(4×219×
20
219
)−4000
=(9592.2−4000)rs
=5592.2rs
hope this helps...
Answered by
0
Answer:
4796
explained
4000(1+19/2/100)^2
4000(219/200)^2
4000(1.99025)^2
4000*1.99025
4796
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