Shyam found that the HCF of two numbers is 21 and their LCM is 129 is it possible give reasons
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LCM of two should be exactly divisible by their HCF. However, 129 leaves a remainder 3 when divided with 21. Hence, the given situation is not possible.
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LCM of two should be exactly divisible by their HCF. However, 129 leaves a remainder 3 when divided with 21. Hence, the given situation is not possible.
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