Math, asked by ritikakumari14, 7 months ago

Shyam found that the HCF of two numbers is 21 and their LCM is 129 is it possible give reasons​

Answers

Answered by arabiayman
1

Answer:

LCM of two should be exactly divisible by their HCF. However, 129 leaves a remainder 3 when divided with 21. Hence, the given situation is not possible.

Step-by-step explanation:

Answered by atantyatanty
3

LCM of two should be exactly divisible by their HCF. However, 129 leaves a remainder 3 when divided with 21. Hence, the given situation is not possible.

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