Question

Shyam's house, his office and his gym are all equidistant from each other. The distance between any 2 of them is 4 km. Shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office. He then reverses direction and walks till he reaches a point directly south of his office. The total distance walked by shyam is * 1 point

Answer 1

Answer:

12 km

Step-by-step explanation:

Shyam's house, his office and his gym are all equidistant from each other. The distance between any 2 of them is 4 km. Shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office. He then reverses direction and walks till he reaches a point directly south of his office

To Simplify Lets Assume that

    O ffice is on North axis

& House on West  &  Gym is on East

When He starts from GYM and Reaches East to office

=> He has walked equal to distance between House & Office = 4 km

Then 4 km to return at GYM

Then 4 km to reach south of his office

4 + 4 + 4 = 12 km

The total distance walked by shyam is 12 km