Question

Shyam's house, his office and his gym are all equidistant from each other. the distance between any 2 of them is 4 km. shyam starts walking from his gym in a direction parallel to the road connecting his office and his house and stops when he reaches a point directly east of his office.he then reverses direction and walks till he reaches a point directly south of his office. the total distance walked by shyam is

Answer 1

Acc to the question, it is pretty obvious that the three places are the three vertices of an equilateral triangle with each side = 4km.

Then only all can be equidistant from each other.

I've attached an image, where O denotes office, H denotes House and G denotes gym.

Now, it is said that shyam starts walking from his gym in a direction parallel to the road connecting his office and his house . The path traversed is P1,G,P2.

Shyam stops when he reaches a point directly east of his office.he then reverses direction and walks till he reaches a point directly south of his office.

Therefore, the total distance walked by shyam will be sum of distance of (G to P1, P1 to G and G to P2) = 4 + 4 + 4 = 12 km.    [Ans]