Question

shyam takes 2 rounds of a square park of side 135m and seema takes 3 rounds of a rectangular park of length 70m and breadth 45m. who cover more distance and by how March

Answer 1

For shyam

Side = 135 cm
Perimeter = 4 × side
= 4 × 135
= 540
He takes 2 rounds of park
therefore distance covered by syam = 540 × 2
= 1080

For seema

l = 70 m
b = 45 m
Perimeter = 2(l+b)
= 2(70+45)
=2×115
=230 m

She takes 3 rounds of park
therefore distance covered by seema = 230×3
= 690 m

Seema covered more distance by
690 - 230
460 m


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Answer 2

Hope you understood.