Question

Shyam was 3 times older than his son in 2003. Ten years later, he is twice as old as his son. Find the present age of Shyam and his son.

Answer 1

let Shyam son age in 2003=x
Shyam age in 2003=3x
ten years later-
son age =x+10
his age= 3x+10
a.to.q.
after 10 years
his age=2(x+10)
3x+10=2x+20
3x-2x=20-10
x=10
son age =10
Shyam age=3*10=30