Question

Shyama bought two ribbions measuring 43/6m and 27/4m respectively . she used 35/3 out of it on her doll. how much ribbon is left with her​

Answer 1

➤ Answer :-

Total ribbon left with Shyama :-

$⇢ \sf \frac{43}{6} + \frac{27}{4} - \frac{35}{3}$

LCM of 6,4 and 3 is 12.

$⇢ \sf \frac{43 \times 2}{6 \times 2} + \frac{27 \times 3}{4 \times 3} - \frac{35 \times 4}{3 \times 4}$

$⇢ \sf \frac{86}{12} + \frac{81}{12} - \frac{140}{12}$

$⇢ \sf \frac{86 + 81 - 140}{12}$

$⇢ \sf \frac{167 - 140}{12}$

$⇢ \sf\frac{127}{12} = 10 \frac{7}{12}$

$\Huge\therefore$$\sf 10 \frac{7}{12}$ metre of ribbon is left with Shyama.

Answer 2

$\huge{\boxed{\fcolorbox{cyan}{pink}{answer}}}$

Total ribbon left with Shyama :

$= > \: \: \frac{43}{6} + \frac{27}{4} - \frac{35}{3}$

LCM of 6,4 and 3 is 12

$= > \: \: \frac{43 \times 2}{6 \times 2} + \frac{27 \times 3}{4 \times 3} - \frac{35 \times 4}{3 \times 4}$

$= > \: \: \frac{86}{12} + \frac{81}{12} - \frac{140}{12}$

$= > \: \: \frac{86 + 81 - 140}{12}$

$= > \: \: \frac{167 - 140}{12}$

$= > \: \: \frac{127}{12 } = 10 \frac{7}{12}$

$\: therefore \: \: 10\frac{7}{12} meters \:of \: ribbon \: left \: with \: shyama.$

hope this will help you...

-3idiots29