Question

SI A Sin
10. In A PQR, right-angled at Q. PR + QR = 25 cm and PQ = 5 cm. Determine the values of
sin P. cos P and tan P.​

Answer 1

Answer:

in right ∆PQR

PR=(25-QR)cm

PQ=5cm

Now,by PT.

PR²=PQ²+QR²

(25-QR)²=5²+QR²

625-50QR+QR²=25+QR²

50QR=625-25

50QR=600

QR=12cm

PR=25-12=13cm

sinP=12/25,cosP=5/25,tanP=12/5