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CH4 + 2O2 → CO2 + 2H2O
1 V 2 V 1 V
2C2H2 + 5O2 → 4CO2 + 2H2O
2 V 5 V 4 V
From the equations, we can see that
1V CH4 requires oxygen = 2 V O2
So, 10cm3 CH4 will require =20 cm3 O2
Similarly 2 V C2H2 requires = 5 V O2
So, 10 cm3 C2H2 will require = 25 cm3 O2
Now, 20 V O2 will be present in 100 V air and 25 V O2 will be present in 125 V air ,so the volume of air required is 225cm3
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The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).
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