Question

si cos (a+b) =3/2 y cos (a-b) =1/2 calcular cosaxcosb​

Answer 1

Answer:

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Answer 2

Answer:

cosa×cosb=1

Step-by-step explanation:

we know that cos(a+b)=[cosa×cosb]-[ sina×sinb] ---------(1)

and cos(a-b)=[cosa×cosb]+[sina×sinb]-------------(2)

According to question, cos(a+b)=3/2 and cos(a-b)=1/2

so adding equation 1 and 2 we get that, 2cosa×cosb=3/2+1/2=4/2=2

so cosa×cosb=2/2=1