Question

si - Example 6 : Find the dimensions of the prayer hall discussed in Section 10.1. Solution : In Section 10.1, we found that if the breadth of the hall is x m, then x satisfies the equation 2x2 + x - 300 = 0. Applying the factorisation method, we write this equation as 2x2 - 24x + 25x - 300 = 0 2x (x - 12) + 25 (x - 12) = 0 i.e., (x - 12)(2x + 25) = 0 So, the roots of the given equation are x = 12 or x = -12.5. Since x is the breadth of the hall, it cannot be negative. Thus, the breadth of the hall is 12 m. Its length = 2x + 1 = 25 m. - - --you can explain these question ​

Answer 1

Answer:

2/X is correct answer

Explanation:

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