Question

Si f(x-2)=x^2+3x-2 ; f(k)=k+1
Calcular el valor de k^2+6k+12

Answer 1

Step-by-step explanation:

The two equations can be written as

x

2

(6k+2) + rx +(3k-1) = 0 ...(1)

and x

2

{12k + 4) + px + (6k - 2) = 0. ...(2)

Divide by 2

∴ x

2

(6k+2)+

2

p

x + {3k-1)=0 ...(3)

Comparing (1) and (3), we get r =

2

p

∴ 2r-p = 0.