Question

SI = Rs. 800, R-10% per annum, T= 2 years
b) Find the​

Answer 1

Step-by-step explanation:

❤ Given :-

• Simple interest = $\sf\red{ Rs. 800 }$
• Rate of interest = $\sf\blue{ 10 }$ %
• Time = $\sf\orange{ 2 }$ years

We know that ,

❤ Principle = $\frac{100 \: \times \: Simple \: interest \: }{ Rate \: of \: interest \: \times \: Time }$

❤ Principle = $\frac{ 100 \: × \: 800 }{ 10 \: × \: 2 }$

❤ Principle = $\frac{ 80,000 }{ 20 }$

❤ Principle = $\frac{ 8,000 }{ 2 }$

❤ Principle = Rs. 4000

Answer 2

Correct Question :-

• Simple interest = Rs 800, rate = 10% per annum and time = 2 years. Find the principal and amount.

Answer :-

• The principal = Rs 4000.
• The amount = Rs 4800.

To find :-

• The simple interest and amount.

Step-by-step explanation :-

• Before finding the amount, let's find the principal!

We know that :-

$\underline{ \boxed{ \sf SI = \dfrac{Principal \times Rate \times Time}{100}}}$

Here,

• Simple interest = Rs 800.
• Rate = 10% per annum.
• Time = 2 years.

• Let the principal be p.

----------------------

Substituting the given values in this formula,

$\rm800 = \dfrac{p \times 10 \times 2}{100}$

Multiplying 10 with 2,

$\rm800 = \dfrac{p \times 20}{100}$

Multiplying 20 with p,

$\rm800 = \dfrac{20p}{100}$

Transposing 100 from RHS to LHS, changing it's sign,

$\rm800 \times 100 = 20p$

Multiplying 800 with 100,

$\rm80000 = 20p$

Transposing 20 from RHS to LHS, changing it's sign,

$\rm \dfrac{80000}{20} = p$

Dividing 80000 by 20,

$\overline{ \boxed{ \rm Rs \: 4000 = p}}$

----------------------

• Now, as we know the principal, let's find the amount!

We know that :-

$\underline{ \boxed{ \sf Amount = Principal + Interest}}$

Here,

• Principal = Rs 4000.
• Interest = Rs 800.

Hence,

$\boxed{\bf Amount = 4000 + 800}$

$\overline{ \boxed{\bf Amount = Rs \: 4800}}$