Question

SI. The volume of flow of water per second through a pipe is given by the product of the area
on the cross section of the pipe and the speed of water flowing through it per second. Find
the expression for the volume of flow of water per second through a rectangular pipe having
sides of length (x - 9) cm and (x + 10) cm respectively, if the speed of the water is (x-1) cm/s.​

Answer 1

Answer:

x³-91x+90 cm³/sec

Step-by-step explanation:

area of cross section= lengh× breadth

= (x+10) (x-9)= x²+x-90 cm²

speed of water= (x-1) cm/second

thus, volume of flow of water per second

= area of cross section × speed of water

=( x²+x-90) × (x-1)

= x³+x²-90x-x²-x+90

= x³-91x+90 cm³/second