Question

SI X + Y = 8 et XY = 15 trouvez x ^ 2 + y ^ 2 .​

Answer 1

◙ Il est donné que, ◙

x + y = 8 et xy = 15.

◙ Pour trouver ◙

La valeur de x² + y².

◙ Solution ◙

Nous savons,

x² + y² = (x + y) ² - 2xy

⇒x² + y² = (8) ² - 2 (15)

⇒x² + y² = 64 - 30

$\huge\bold{\boxed{x^2+y^2=34}}$

Answer 2

Answer:

x square +y square

= x square + y square +2xy-2xy

= (x square +y square + 2xy) -2xy

=(x+y)whole square -2xy

= (8)square-15*2

=64-30

=34

Explanation:

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