Question

(siaA –cosecA)( cosA–secA)=1÷tanA+cotA prove this question​

Answer 1

Step-by-step explanation:

LHS

(sinA-cosecA)(cosA-secA)

=(sinA-cosecA)(cosA-secA)

=(sinA-1/sinA)(cosA-1/cosA)

=(sin^2A-1/sinA)(cos^2A-1/cosA)

=cos^2A/sinA × sin^2A/cosA

=cosAsinA

RHS

1/TanA+cotA

=1/sinA/cosA+cosA/sinA

=1/sin^2A+cos^2/cosAsinA

=1/1/cosAsinA

=1×cosAsinA/1

=cosAsinA

LHS=RHS