Question

siddh kijiye ki sin20sin40sin60sin80=3/16​

Answer 1

Answer:

Prove that sin 20*sin40+sin60*sin80=3/16.

sin20. sin 40. sin60. sin80

=> sin60[sin20.sin40.sin80]

=>√3/2[sin20.sin(60-20).sin(60+20)]

=>√3/2[sin 3(20)/4]

=>√3/2[sin 60/4]

=>√3/2[√3/2*4]

=>√3/2*√3/8

=3/16