Siddharth is painting the walls and ceiling of a cuboidal room with length, breadth and height as 20m, 12m, 10m respectively. An area of 80m2 can be painted from each can. Find how many cans of paint will be required to paint the room.
Answers
Answered by
14
l=20,b=12, h = 10
area of ceiling = l*b = 20*12 = 240
area of wall = b*h = 12 *10 = 120
no.of walls = 4
so 120*4= 480
total area = 480+240 = 720
no.of cans needed = 720/80 = 9 cans
area of ceiling = l*b = 20*12 = 240
area of wall = b*h = 12 *10 = 120
no.of walls = 4
so 120*4= 480
total area = 480+240 = 720
no.of cans needed = 720/80 = 9 cans
Answered by
4
Surface area of a cuboidal hall without bottom = Total surface area – Area of base
= 2 [lb + bh + hl] – lb
= 2 [15 × 10 + 10 × 7 + 7 × 15] – 15 × 10
= 2[150 + 70 + 105] – 150
= 2 [325] – 150
= 650 – 150
= 500 m2
Area of the paint in one can = 100 m2
Number of cans required = 500100 = 5 cans.
Similar questions