Side ab of a triangle abc is 80 cm. If the perimeter is 170 and angle abc is 60. Find the shortest side
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Answer:
17 cm
Step-by-step explanation:
Let the remaining side be a and b respectively.
Since the perimeter = 170 cm and one of the side is 80, then
a + b = 90 ---- (1)
Based on cosine rule,
cos 60 = ( a² + 80² - b² ) / ( 2 x a x 80 )
1/2 = ( a² + 80² - b² ) / ( 160 a ) --- (2)
Solving (1) and (2) we get,
a = 17, b = 73
So the smallest side = 17 cm
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