side BC of angleABC has been produced to D on left and to E on right hand side of BC such that
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From the figure we know that ∠DBA and ∠ABC form a linear pair of angles
So we get
∠DBA+∠ABC=180
∘
By substituting the values
106
∘
+∠ABC=180
∘
On further calculation
∠ABC=180
∘
−106
∘
By subtraction
∠ABC=74
∘
From the figure we know that ∠ACB and ∠ACE form a linear pair of angles
So we get
∠ACB+∠ACE=180
∘
By substituting the values
∠ACB+118
∘
=180
∘
On further calculation
∠ACB=180
∘
−118
∘
By subtraction
∠ACB=62
∘
We know that the sum of all the angles in a triangle is 180
∘
.
So we can write it as
∠ABC+∠ACB+∠BAC=180
∘
By substituting the values
74
∘
+62
∘
+∠BAC=180
∘
On further calculation
∠BAC=180
∘
−74
∘
−62
∘
By subtraction
∠BAC=180
∘
−136
∘
∠BAC=44
∘
Therefore, the measure of each angle of the triangle is ∠A=44
∘
,∠B=74
∘
and ∠C=62
∘
.
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