side is 13cm and diagnols are 24cm find area of rhombus
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By Pythagoras theorem, half of second diagonal
12²+diagonal²=13²
Diagonal² =169-144=25
Diagonal =√25=5
Area of rhombus=product of diagonals/2
=10*24=120cm²
12²+diagonal²=13²
Diagonal² =169-144=25
Diagonal =√25=5
Area of rhombus=product of diagonals/2
=10*24=120cm²
1mokshagna1:
area of rhombus
formulae
Area of rhombus=product of diagonals/2
why 10 x 2
sorry 24
If the product of diagonals =24, area =24/2=12
Answered by
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Heya,
Here's your answer.
☆ Given =
side (a) = 13 cm
Diagonal (d) = 24cm
Area of rhombus = ?
☆ We want to find the length if other diagonal.
By Pythagorean theorom,
Other diagonal be x
(12)^2 + (x)^2 = (13)^2
[ 12 as diagonals of the RHOMBUS bisect each other, 24/2 ]
144 + x^2 = 199
x^2 = 169-144
x^2 = 25
x = 5
So, other diagonal = 5×2 = 10
☆ Area of RHOMBUS = 1/2×d1×d2
= 1/2×24×10
= 120 cm^2
Hope it helps.
Here's your answer.
☆ Given =
side (a) = 13 cm
Diagonal (d) = 24cm
Area of rhombus = ?
☆ We want to find the length if other diagonal.
By Pythagorean theorom,
Other diagonal be x
(12)^2 + (x)^2 = (13)^2
[ 12 as diagonals of the RHOMBUS bisect each other, 24/2 ]
144 + x^2 = 199
x^2 = 169-144
x^2 = 25
x = 5
So, other diagonal = 5×2 = 10
☆ Area of RHOMBUS = 1/2×d1×d2
= 1/2×24×10
= 120 cm^2
Hope it helps.
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