Question

side of a rhombus is 10cm and one of tje diagonal is 16cm find the lenght of the other diagonal​

Answer 1

Answer:

Diagonals of a rhombus bisect each other at right angles.

Let ABCD be the rhombus, Diagonal AC=16 cm and side AB=10 cm.

In right △AOB, AB=10 cm, AO=8 cm

By Pythagoras theorem, AB2 = AO2 +BO 2

⇒10(2) =8(2) +BO2

⇒BO(2)=100−64=36

∴BO=6cms

Diagonal BD=2×6=12cm

Area of Rhombus= 2/1 ×(productofthediagonals)

= 2/1 ×16×12=8×12=96sq.cm

Hence ,length of other diagonal =12 cm;

And Area of rhombus =96sq.cm