Side of a rhombus is 13 cm and one diagonal is 10 cm find first the length of its other diagonal second the area of the rhombus
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In rhombus ABCD
AB = 13 cm
AC = 10 cm
OA = 10 × 1/2 = 5 cm
1). By pyathagoras theorem
(AB)^2 = (OA)^2 + (OB)^2
(13)^2 = (5)^2 + X^2
X^2 = 169 - 25
X^2 = 144
X = 12 cm
So OB = 12
So BD = 12 × 2
=> 24 cm
2). Area of rhombus = 1/2 × d1 × d2
=> 1/2 × 10 × 24
=> 120 cm sq
Hope it helps uh...
Thanks....☺☺✌
In rhombus ABCD
AB = 13 cm
AC = 10 cm
OA = 10 × 1/2 = 5 cm
1). By pyathagoras theorem
(AB)^2 = (OA)^2 + (OB)^2
(13)^2 = (5)^2 + X^2
X^2 = 169 - 25
X^2 = 144
X = 12 cm
So OB = 12
So BD = 12 × 2
=> 24 cm
2). Area of rhombus = 1/2 × d1 × d2
=> 1/2 × 10 × 24
=> 120 cm sq
Hope it helps uh...
Thanks....☺☺✌
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