side of a rhombus is 20 cm and one of its diagonals is 24 cm.... find the length of the other diagonal. also it's area??
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Answered by
2
Diagonal = 32
Area of Rhombus = 384
Area of Rhombus = 384
Answered by
2
Let ABCD be the rhombus; BD=24 so, BO= 12 and AD(side) =20
By Pythagoras theorem : AO=16 so, AC= 32 cm
Area= AC*BD/2= 192cm
By Pythagoras theorem : AO=16 so, AC= 32 cm
Area= AC*BD/2= 192cm
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