Question

side of a triangal are in the ratio 3:4:5 perimeter = 144 find area​

Answer 1

Answer:

Let say sides are 3x,4x,5x

Perimeter =144

12x=144

x=12

Sides a=36 b=48 c=60

s=a+b+c/2=72

Area=root(s)(s-a)(s-b)(s-c)

=root72*36*24*12

=6*6*24

=864 unit^2

Answer 2

Answer:

let the side of triangle is = 3x +4x +5×

= 12x

the perimeter is given so,

12x = 144

x = 12

sides are ;-

3x = 3×12

= 36

4x = 4× 12

= 48

5x = 5× 12

= 60

'

S = 36 + 48 + 60/2

S = 144/2

= 72

where s is semiperimeter.

area of triangle =

$\sqrt{72(72 - 36)(72 - 48)(72 - 60)} \: (by \: heron \: formula)$

$\sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3 \times 11}$

=

$2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times \sqrt{22}$

$432\sqrt{22}$

hope it will help you......