Question

side of a triangle are in the ratio 12 : 17 : 25 and its perimeter is 540 cm. find its area.

Answer 1

HEY dude,
your answer is,
Let, the sides of triangle are 12x, 17x, 25x
We know that, 12x + 17x + 25x = 540cm
=>54x = 540cm
=>x = 540/54 cm
=>x = 10 cm
12x = 12×10 cm = 120 cm
17x =17×10 cm = 170 cm
25x = 25×10 cm = 250 cm
s = (120+170+250)/2 = 270 cm
Area of triangle = √270(270-120)(270-170)(270-250)
= 9000 cm^2
PLEASE MARK ME AS BRAINILIEST

Answer 2

$\huge \star{hey \: chika} \star$

Here's ur answer-

Let the sides of ∆ be -

a = 12x
b = 17x
c = 25x

We know that-
$\text{perimeter \: of \: triangle} \\ = \text{sum \: of \: all \: sides}$

So,
$540 = 12x + 17x + 25x \\ 540 = 54x \\ x = 540 \div 54 \\ x \: = 10cm$

Hence, the side measures are -

a = 12 × 10 = 120cm
b = 17 × 10 = 170 cm
c = 25 × 10 = 250cm
_____________________________

Now, finding area
$= \sqrt{s(s - a)(s - b)(s - c)}$
S [semi-perimeter]
$(a + b + c \:) \div 2$
$= 540 \div 2 \\ = 270cm$

Area of ∆ =
$= \sqrt{270(270 - 120)(270 - 170)(270 - 250)} \\ = \sqrt{270 \times 150 \times 100 \times 20} \\ = \sqrt{81000000} \\ = 9000cm {}^{2}$
Hope it helps ✔