Question

side of. a. triangle. are in. the. ratio 2:3:4 and it's. perimeter is 90 m. find its. area​

Answer 1

Step-by-step explanation:

Let Assume 2:3:4 as 2x 3x 4x and perimeter = 90 then 9x=90,x=90/9= 10

2×10 = 20

3×10 = 30

4×10 = 40

By using semiperimeter formula s= sum of side/2

40+20+30/2=45

by using herons formula we can easily find the area now see it carefully cause I can't type the way I do it in notebook...

Area =√s(s-a)(s-b)(s-c)

√45(45-20)(45-30)(45-40)

√45(25)(15)(5)

3×3×5×5×5×3×5×5×1

those students who are weak in this just make the pair and those who didn't make pair don't take them keep them seperately... Now see carefully

we have one pair of 3 and two pair of 5 then take one 3 and two 5

3×5×5√5×3×1

75√15 plz match the anwer if it is wrong then tell me I will answer it by another method

It was too hard to write Plz support its the real talent I m in class 9 and solving and helping you guys Thanks alot

Answer 2

Let the common ratio = x

Sides becomes = 2x ,3x, 4x,

Perimeter of triangle = sum of sides

90 = 2x + 3x +4x

90 = 9x

90/9 = x

10 = x

So now sides

20 , 30 and 40

Area of the triangle is square root of s (s-a)(s-b)(s-c) where s is 1/2 (a+b+c),

s = 1/2 ( 20 + 30+ 40) =1/2 (90) = 45

Therefore area = sq.root of 45 (45–20)(45- 30)(45- 40)

=sq.root of 45×25×15×5. = 290.