Math, asked by kulsoomnaaz05, 22 hours ago

side of a triangle are in the ratio 2:3:4 of it's perimeter is 225m find the length of smallest side

full explanation please on paper​

Answers

Answered by HelperSoham
2

Step-by-step explanation:

Length of one side =2x

Length of second side =3x

Length of third side =4x

Perimeter of triangle=225m

ATQ

Perimeter of triangle =side 1+side2+side3

225=2x+3x+4x

225=9X

225/9=X

25=X

X=25

LENGTH of one side =2x=25*2=50

Second side =3x=25*3=75

Third side =4x=25*4=100

Now find the area of triangle=

.

\sqrt{s(s - a)(s - b)(s - c) }s(s−a)(s−b)(s−c)

S =perimeter of triangle /2 = 225/2 =112.5

=

\sqrt{112.5(112.5 - 50)(112.5 - 75)(112.5 - 100)}112.5(112.5−50)(112.5−75)(112.5−100)

=

\sqrt{112.5 \times 62.5 \times 37.5 \times 12.5}112.5×62.5×37.5×12.5

=

\sqrt{3295898.4375}3295898.4375

=1815.46

{m}^{2}m2

Answered by poonamguptapoonam1
0

Step-by-step explanation:

full explanation on paper

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