side of a triangle are in the ratio 2:3:4 of it's perimeter is 225m find the length of smallest side
full explanation please on paper
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Step-by-step explanation:
Length of one side =2x
Length of second side =3x
Length of third side =4x
Perimeter of triangle=225m
ATQ
Perimeter of triangle =side 1+side2+side3
225=2x+3x+4x
225=9X
225/9=X
25=X
X=25
LENGTH of one side =2x=25*2=50
Second side =3x=25*3=75
Third side =4x=25*4=100
Now find the area of triangle=
.
\sqrt{s(s - a)(s - b)(s - c) }s(s−a)(s−b)(s−c)
S =perimeter of triangle /2 = 225/2 =112.5
=
\sqrt{112.5(112.5 - 50)(112.5 - 75)(112.5 - 100)}112.5(112.5−50)(112.5−75)(112.5−100)
=
\sqrt{112.5 \times 62.5 \times 37.5 \times 12.5}112.5×62.5×37.5×12.5
=
\sqrt{3295898.4375}3295898.4375
=1815.46
{m}^{2}m2
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Step-by-step explanation:
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