side of a triangle are in the ratio 4:5:5 and its perimeter is 168 M find the area of triangle
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Sides Of The triangle are In The ratio 4x , 5x , 5x
area of triangle = a + b + c / 2
4x + 5x + 5x = 168
14x = 168
x = 168 / 14
x = 12
4x = 12 * 4.= 48
5x = 12 *5 = 60
5x = 12 *5 = 60
using herons formula
√s( S -a) (S -b) (S -c)
√12 ( 12 -48) ( 12 - 60) (12 -60)
√12 * 36 * 48 * 48
√2*2 *3 2*2 *3*3 *2*2*2*2*3 *2*2*2*2*3
√2*2*2*2 *2*2*2*2*2*2 *2 *2*3 3*3*3*3*
make perfect square
64√9 cm²
area of triangle = a + b + c / 2
4x + 5x + 5x = 168
14x = 168
x = 168 / 14
x = 12
4x = 12 * 4.= 48
5x = 12 *5 = 60
5x = 12 *5 = 60
using herons formula
√s( S -a) (S -b) (S -c)
√12 ( 12 -48) ( 12 - 60) (12 -60)
√12 * 36 * 48 * 48
√2*2 *3 2*2 *3*3 *2*2*2*2*3 *2*2*2*2*3
√2*2*2*2 *2*2*2*2*2*2 *2 *2*3 3*3*3*3*
make perfect square
64√9 cm²
nidhi312:
but answer is not correct
I can give correct answer
The area of given triangle can be calculated using Heron's Formula
Answered by
5
Answer:
Sides Of The triangle are In The ratio 4x , 5x , 5x
area of triangle = a + b + c / 2
4x + 5x + 5x = 168
14x = 168
x = 168 / 14
x = 12
4x = 12 * 4.= 48
5x = 12 *5 = 60
5x = 12 *5 = 60
using herons formula
√s( S -a) (S -b) (S -c)
√12 ( 12 -48) ( 12 - 60) (12 -60)
√12 * 36 * 48 * 48
√2*2 *3 2*2 *3*3 *2*2*2*2*3 *2*2*2*2*3
√2*2*2*2 *2*2*2*2*2*2 *2 *2*3 3*3*3*3*
make perfect square
64√9 cm²
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