Question

Side of a triangle are in the ratio of 12:17:25 and it's perimeter is 540. find it's area ​

Answer 1

Answer:

Answer

⇒Let x be common ratio

∴ Sides of triangle will be: 12x,17x and 25x

⇒Perimeter =540 cm(given)

⇒12x+17x+25x=540 cm,

⇒54x=540 cm

⇒x=10 cm

∴ Sides of triangle: a=120,b=170,c=250 cms

⇒2S=540

⇒S=270 cm

A=

s(s−a)(s−b)(s−c)

=

270(270−120)(270−170)(270−250)

cm

2

=

270×150×100×20

cm

2

A=9000 cm

2

Step-by-step explanation:

please mark as brainlist.

Answer 2

Answer:

Step-by-step explanation:

let the sides of a triangle be = 12x,17x,25x

perimeter of triangle=540 units

12x+17x+25x=540

54x=540

x=10

sides are = 120 units, 170 units, 250 units

area of triangle = > heron's formula

s= (120+170+250)/2

=270  units

$\sqrt{270(270-120)(270-170)(270-250)}\\\sqrt{270*100*20} \\\sqrt{3*3*3*10*10*10*2*10} \\300\sqrt{6}$

300√6 unit ²