side of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540 cm find its area
saurav1000:
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Answered by
16
12:17:25
perimeter = 540
let a=12x
b=17x
c=25x
perimeter=a+b+c
540=12x+17x+25x
540=54x
x=540/54 =10
x=10
therefore, a=12*10=120
b= 17*10=170
c= 25*10=250
SEMI-PERIMETER = 540/2=270
note: area is founded in upper image
I hope that this will be helpful to you.....
perimeter = 540
let a=12x
b=17x
c=25x
perimeter=a+b+c
540=12x+17x+25x
540=54x
x=540/54 =10
x=10
therefore, a=12*10=120
b= 17*10=170
c= 25*10=250
SEMI-PERIMETER = 540/2=270
note: area is founded in upper image
I hope that this will be helpful to you.....
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Answered by
5
12x+17x+15x=540
44x=540
x=540 /44
area =√s×s-a*s-b*s-c
s= 540/2
=270
44x=540
x=540 /44
area =√s×s-a*s-b*s-c
s= 540/2
=270
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