Question

side of an equilateral triangle is 8cm find the side of an equilateral triangle where area is twice the area of first​

Answer 1

Step-by-step explanation:

According to the Heron's formula, Area (A) of the triangle having sides a,b,c units is 

A=s(s−a)(s−b)(s−c)

where

s=2a+b+c

For the given triangle,

a=b=c=8cm

s=28+8+8=12

A=12(12−8)(12−8)(12−8)

A=3×4×43

=4×43

=163

Area of the triangle =21×base×altitude=163

21×8× altitude=163

Altitude =4163=43

Answer 2

Answer:

$\sqrt{3} a^2/4$ =area

a=8

$\sqrt{3} 8^2/4$=area

16$\sqrt{3}$=area

new AREA=2 old area

$\sqrt{3} a^2/4$=2*8^2$\sqrt{3}$/4

a=16