Question

side of atriangle are cm 45 cm,39cm and 42cm,find its area​

Answer 1

s=a+b+c divide by 2

s=45+39+42 divide vy2

s= 126/2

s=63

area=√s(s-a)(s-b)(s-c) ....(so route under s*s-a*s-b*s-c)

=√63(63-45)(63-39)(63-42)

=√63*18*24*21

=756sqcm