Question

Side of equilateral triangle is 4 cm and square inside is of 1 cm side each as

shown in figure.​

Answer 1

Answer:

⇒  Side of a square, ABCD=4cm

It is given that △CED is an equilateral triangle.

∴  EC=CD=DE=4cm

⇒  ∠ECD=60o.          [ An angle of an equilateral triangle ]

AC is a diagonal of a square ABCD

∴  ∠ACD=45o.

⇒  ∠ECA=∠ECD−∠ACD

⇒  ∠ECA=60o−45o

⇒  ∠ECA=15o

In △ACE, draw perpendicular EM the base AC.

Now in △EMC,

⇒  sin15o=HP=ECEM

⇒  sin15o=4EM

⇒  22(3−1)=4EM

⇒  (3−1)×(2

Step-by-step explanation:

May be this will hlp u

Answer 2

Answer:

your ans. is on top photo