Question

side of rhombus is 10cm , d1 is 12 cm find its area .​

Answer 1

The diagonals in a rhombus are perpendicular , and bisect each other

Given length of side is 10 cm and one diagonal as 12 cm we can find the length of other diagonal

From the above figure let DB be the 12 cm diagonal,now OB and OD are 6 cm

Now consider triangle AOB ,this is a right andled triangle and we know AB=10cm and OB=6cm ,using Pythagoras theorem we can find out lenth of OA as 8cm ,so length of diagonal AC is 2*8=16cm

Area of rhombus is product of diagonal divided by 2, 16*12/2=96 sq.cm

Answer 2

Answer:

Area of rhombus = 120$cm^{2}$

Step-by-step explanation:

According to the information provided in the question it is given as

Side of Rhombus is 10cm , d1 is 12 cm

We need to find its area .​

First understand the shape rhombus

A rhombus is a special case of a parallelogram, and it is a four-sided quadrilateral. In a rhombus, opposite sides are parallel .

A quadrilateral with all four sides equal in length.

Here side = 10 cm

Diagonal  = 12 cm

Now applying formula of area of rhombus

A = p q /2  (using diagonals)

Where p and q  = diagonal  = 12 cm

A =  b x h  

     As  diagonal is nothing but height = 12 cm

       base is nothing but the side  = 10 cm

Substituting the values we get the area of rhombus

$A = 10 \times 12\\A = 120 cm^{2}$

Hence area of rhombus is 120$cm^{2}$