Question

Side of rohombous is 13 cm and sum of diagonals are 34 cm area​ is

Answer 1

Answer:

Step-by-step explanation:

 The diagonals of rhombus bisect each other at right angle.

Let ABCD is a rhombus with diagonals AC and BD which intersect each other at O.

AC = 10 cm , OA =1/2×AC=

OA= (½) × 10= 5 cm

OA= 5 cm

AB = 13 cm (given)

In ∆ AOB

By Pythagorean theorem

AB²= 0B²+ OA²

13² = OB² + 5²

169 = OB² + 25

OB²= 169 – 25

OB² =144

OB= √144

OB= 12 cm

Diagonal BD = 2 x 12= 24 cm

Hence, the length of other Diagonal = 24 cm

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