Side of rohombous is 13 cm and sum of diagonals are 34 cm area
Answers
Answered by
4
Step-by-step explanation:
By Pythagoras theorem,
H² = P²+B² (where P and B are sides of rhombus and H is a diagonal)
H² = 13²+13² (since rhombus have equal length of all sides)
H² = 169+169
H² = 338
H = √338
H = 18.38 cm
Area = (p×q)/2. (where p and q are diagonals)
= 18.38 × 18.38 (diagonals are same in rhombus)
= 338 cm²
Similar questions