Question

Side of rohombous is 13 cm and sum of diagonals are 34 cm area​

Answer 1

Step-by-step explanation:

By Pythagoras theorem,

H² = P²+B² (where P and B are sides of rhombus and H is a diagonal)

H² = 13²+13² (since rhombus have equal length of all sides)

H² = 169+169

H² = 338

H = √338

H = 18.38 cm

Area = (p×q)/2. (where p and q are diagonals)

= 18.38 × 18.38 (diagonals are same in rhombus)

= 338 cm²